阿多米安分解法

阿多米安分解法（Adomian decomposition method，简称：ADM法），是1989年美国籍阿马尼亚数学家George Adomian创建的近似分解法，用以求解非线性偏微分方程

将非线性偏微分方程写成如下形式：

$L(u)+R(u)+NL(u)=g(x,t)$

其中 L、R为线性偏微分算子，NL为非线性项。 将反算子$L^{-1}=\underset{0}{\overset{t}{\int }}()$. 用于上式

$L^{-1}L(u)=-L^{-1}R(u)-L^{-1}NL(u)+L^{-1}g(x,t)=$.

得

$u(x,t)=u(x,0)-L^{-1}NL(u)+L^{-1}g(x,t)$.

令方程的解u（x,t) 为：

$u=u_0+u_1+u_2+u_3+\cdots$

非线性项

NL（u）=$A_0+A_1+A_2+\cdots$

其中

$A_n=\frac{1}{n!}\frac{{\mathrm{d}}^n}{\mathrm{d}{\lambda }^n}f(u(\lambda )){\mid }_{\lambda =0},$

$\frac{{\mathrm{d}}^n}{\mathrm{d}{\lambda }^n}u(\lambda ){\mid }_{\lambda =0}=n!u_n$

由此得

$u(x,t)=u(x,0)+L_{-1}g(x,t)$

$u_1(x,t)=-L^{-1}R{u}_0-L^{-1}{A}_0$

$u_n(x,t)=-L^{-1}R{u}_{n-1}-L^{-1}{A}_{n-1}$

近似解=$u_0(x,t)+u_1(x,t)+u_2(x,t)+u_3(x,t)+\cdots$

Burgers-Fisher 方程 ADM解

Burgers-Fisher方程：

$\frac{\partial u}{\partial t}+u^2*\frac{\partial u}{\partial x}-\frac{{\partial }^{2}u}{\partial u^2}=u*(1-u^2)$

$u[0]=tanh(x)$

$u[1]=-tanh(x)*(1-tanh(x{)}^2)*t$

$u[2]=-(1/2)*t^2*tanh(x)*(-1+tanh(x{)}^2)*(2-4*tanh(x{)}^2)$

$u[3]=-(1/3)*t^3*tanh(x)*(3-16*tanh(x{)}^2+26*tanh(x{)}^4-13*tanh(x{)}^6-3*tanh(x{)}^2*(1-tanh(x{)}^2)+(2*(1-tanh(x{)}^2))*tanh(x{)}^4)$

近似解：

pa := (-1.*tanh(x)-82360.*tanh(x)^13+73.*tanh(x)^3-1195.*tanh(x)^5+8233.*tanh(x)^7-29990.*tanh(x)^9+63510.*tanh(x)^15-26980.*tanh(x)^17+4862.*tanh(x)^19+63850.*tanh(x)^11)*t^9+(14650.*tanh(x)^13-16170.*tanh(x)^11+tanh(x)+1430.*tanh(x)^17+688.8*tanh(x)^5+10230.*tanh(x)^9-7102.*tanh(x)^15-54.67*tanh(x)^3-3672.*tanh(x)^7)*t^8+(-373.8*tanh(x)^5+1491.*tanh(x)^7-1.*tanh(x)+39.67*tanh(x)^3+3333.*tanh(x)^11+429.*tanh(x)^15-3036.*tanh(x)^9-1881.*tanh(x)^13)*t^7+(132.*tanh(x)^13+187.8*tanh(x)^5-502.*tanh(x)^11+743.5*tanh(x)^9-27.67*tanh(x)^3+tanh(x)-534.6*tanh(x)^7)*t^6+(-135.3*tanh(x)^9+161.1*tanh(x)^7-1.*tanh(x)+42.*tanh(x)^11-85.13*tanh(x)^5+18.33*tanh(x)^3)*t^5+(-37.*tanh(x)^7+33.33*tanh(x)^5+14.*tanh(x)^9-11.33*tanh(x)^3+tanh(x))*t^4+(5.*tanh(x)^7-10.33*tanh(x)^5+6.333*tanh(x)^3-1.*tanh(x))*t^3+(-3.*tanh(x)^3+tanh(x)+2.*tanh(x)^5)*t^2+(-1.*tanh(x)+tanh(x)^3)*t+tanh(x)

迪姆方程ADM解

迪姆方程：

$u_t=u^3{u}_{xxx}.$

$u[0]=cosh(x)$

$u[1]=-cosh(x)*sinh(x)*t$

$u[5]=-t^5*cosh(x)*sinh(x{)}^5-(20/3)*t^5*cosh(x{)}^3*sinh(x{)}^3-(47/15)*t^5*cosh(x{)}^5*sinh(x)$

${\displaystyle }$

ADM近似：

u（x,t)~pa := (-.5382*sinh(10.*x)-.7224*sinh(8.*x)-.2441*sinh(6.*x)-0.5787e-4*sinh(2.*x)-0.1693e-1*sinh(4.*x))*t^9+(.4634*cosh(9.*x)+0.5933e-2*cosh(3.*x)+.5585*cosh(7.*x)+.1514*cosh(5.*x)+0.1356e-5*cosh(x))*t^8+(-.4063*sinh(8.*x)-0.8889e-1*sinh(4.*x)-.4339*sinh(6.*x)-0.1389e-2*sinh(2.*x))*t^7+(0.1085e-3*cosh(x)+0.4746e-1*cosh(3.*x)+.3647*cosh(7.*x)+.3391*cosh(5.*x))*t^6+(-0.2083e-1*sinh(2.*x)-.2667*sinh(4.*x)-.3375*sinh(6.*x))*t^5+(.3255*cosh(5.*x)+0.5208e-2*cosh(x)+.2109*cosh(3.*x))*t^4+(-.3333*sinh(4.*x)-.1667*sinh(2.*x))*t^3+(.3750*cosh(3.*x)+.1250*cosh(x))*t^2-.5000*t*sinh(2.*x)+cosh(x)