描述050329-birthday1.png	English: The birthday paradox: p(n) represents the probability that in a room with n people, some two (or more) will share the same birthday; q(n) represents the probability that in a room with n people, that at least one person will have the same birthday as a previously selected person. 中文：​生日悖论 2个人生日相同和跟某人生日形同的概率变化
日期	2005年3月29日
来源	self-made by en:User:Wzwz
作者	en:User:Wzwz
授权 (二次使用本文件)	Public domainPublic domainfalsefalse 我，本作品著作权人，释出本作品至公有领域。这适用于全世界。 在一些国家这可能不合法；如果是这样的话，那么： 我无条件地授予任何人以任何目的使用本作品的权利，除非这些条件是法律规定所必需的。
其他版本	File:Birthday paradox.svg是此文件的矢量版本。 如果此文件质量不低于原点阵图，就应该将这个PNG格式文件替换为此文件。 File:050329-birthday1.png → File:Birthday paradox.svg 更多信息请参阅Help:SVG/zh。 其他语言 Alemannisch ∙ العربية ∙ беларуская (тарашкевіца) ∙ български ∙ বাংলা ∙ català ∙ нохчийн ∙ čeština ∙ dansk ∙ Deutsch ∙ Ελληνικά ∙ English ∙ British English ∙ Esperanto ∙ español ∙ eesti ∙ euskara ∙ فارسی ∙ suomi ∙ français ∙ Frysk ∙ galego ∙ Alemannisch ∙ עברית ∙ हिन्दी ∙ hrvatski ∙ magyar ∙ հայերեն ∙ Bahasa Indonesia ∙ Ido ∙ italiano ∙ 日本語 ∙ ქართული ∙ 한국어 ∙ lietuvių ∙ македонски ∙ മലയാളം ∙ Bahasa Melayu ∙ မြန်မာဘာသာ ∙ norsk bokmål ∙ Plattdüütsch ∙ Nederlands ∙ norsk nynorsk ∙ norsk ∙ occitan ∙ polski ∙ prūsiskan ∙ português ∙ português do Brasil ∙ română ∙ русский ∙ sicilianu ∙ Scots ∙ slovenčina ∙ slovenščina ∙ српски / srpski ∙ svenska ∙ தமிழ் ∙ ไทย ∙ Türkçe ∙ татарча / tatarça ∙ українська ∙ vèneto ∙ Tiếng Việt ∙ 中文 ∙ 中文（中国大陆） ∙ 中文（简体） ∙ 中文（繁體） ∙ 中文（马来西亚） ∙ 中文（新加坡） ∙ 中文（臺灣） ∙ +/−

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• (del) (cur) 22:21, 29 March 2005 . . en:User:Wzwz Wzwz ( en:User_talk:Wzwz Talk) . . 463x271 (2994 bytes) (it's pd generated with home.arcor.de/wzwz.de/einzel/birthday.zip ( also pd ))

• 18:04, 26 March 2006 Rei-artur
• 04:38, 26 December 2005 Bash (at least i THINK 'pd' refers to public domain; author doesnt claim copyright on the software either, so its a safe bet)
• 00:05, 30 March 2005 212.144.154.171 (sorry - once again wzwz, logged out)
• 23:21, 29 March 2005 Wzwz (it's pd generated with home.arcor.de/wzwz.de/einzel/birthday.zip ( also pd ))